[Physics Equlibrium Question] A spider hanging from two silk threads

AI Thread Summary
A spider is suspended by two silk threads, with a gravitational force of 0.170 N acting on it. The tension in one thread is given as 0.104 N, but the calculations for the tension in the other thread and the angles with the horizontal are problematic due to missing information. The angles between the threads are not sufficient to solve the problem without knowing the angle of at least one thread relative to the horizontal or vertical. The discussion highlights confusion over variable values and the need for additional data to arrive at a correct solution. Ultimately, the user found the solution elsewhere and shared a link for reference.
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[Physics Equlibrium Question] ***[SOLVED]***

***[SOLVED]***

Hey, I haven't used a forum before, but out of desperation to find the solution/hint to this problem; google brought me here. I would really appreciate any help, as I am I not getting the correct answer. Thank you.

***[SOLVED]***

Homework Statement



Question:
In the figure below, a spider is resting after starting to spin its web. The gravitational force on the spider is 0.170 N on the junction of the three strands of silk. The junction is supported by different tension forces in the two strands above it so that the resultant force on the junction is zero. The two sloping strands are perpendicular, and we have chosen the x and y directions to be along them. The tension Tx is 0.104 N.

Find the Find the tension Ty, find the angle the x-axis makes with the horizontal and Find the angle the y-axis makes with the horizontal.

I attached a picture of the diagram and my FBD of the situation.

Homework Equations



∑Fx=0
∑Fy=0
Θ1+Θ2=90° (Equation 1)
∑Fx=0.104sin(Θ1)-[(T2)sin(Θ2)]=0 (Equation 2)
∑Fy=0.104cos(Θ1)-[(T2)cos(Θ2)]-0.15=0 (Equation 3)


The Attempt at a Solution



*EDITED.

Θ1=Θ2-90° (Rearranged equation 1)

0.127sin(Θ2-90°)-[(T2)sin(Θ2)]=0 (Equation 2, subbed rearranged equation 1 into Θ1)

T2= [0.104sin90°-0.104sin(Θ2))/sin(Θ2)] (Rearranged equation 2 to solve for T2)
T2= 0.104sin90°-0.104=0 (I GET ZERO HERE?)
--NOTE:the below is not edited for the correct value of T1=0.104N because the above is incorrect for some reason now.. I don't know how to proceed now.

0.127cos(Θ1)-[(T2)cos(Θ2)]-0.15=0 (Equation 3)
0.127cos(Θ1)-[(-0.12353)cos(Θ2)]-0.15=0 (subbed new T2 value into Equation 3)

0.127cos90°-0.127cos(Θ2)+(-0.1235)cos(Θ2)-0.15=0 (subbing in known values to find Θ2)
-0.2505cos(Θ2)=0.15+0.127cos(90°)
Θ2=cos^-1[[0.15+0.127cos(90°)]/(-0.2505)]
Θ2=95.28° (this angle does not make sense )

***[SOLVED]***
 

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I think you are missing some information. Having the angle between the supporting threads is not enough information to solve the problem. You need to know the angle between one the threads, w.r.t. either the horizontal or vertical.

The given tension in one of the threads is 0.104 N. It's not clear where 0.127 N comes from in your calculations.
 
SteamKing said:
I think you are missing some information. Having the angle between the supporting threads is not enough information to solve the problem. You need to know the angle between one the threads, w.r.t. either the horizontal or vertical.

The given tension in one of the threads is 0.104 N. It's not clear where 0.127 N comes from in your calculations.

opps sorry I meant 0.104N instead of 0.127N and that is all the information the the question gave me. I'll input the correct values now.
 
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