- #1

donniemateno

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just wondering has anyone studied this physics experiment before? I have to do it as part of my last year at uni as I didnt do physics at college ( chose mechanics much more interesting!)

anyway its apparently been the same exam for the last 4/5 years but the lecturers give you no help in advance and just give you this equation:

T = 2 * Pi * sqrt(l / g)

T = period (in seconds)

Pi = 3.14...

sqrt = root of ...

l = length of pendulum in m

g = acceleration in m/s^2 (9.81)

I am wondering if anyone has done this experiment but working out G rather than t? if so what would the formula be rearranged? I have found 2 through some googling :

1. g = l/(t/tpi)^2

2. g = 4pi^2L/T^2

Sorry if this is in the wrong section please move if it is