Physics Forces Question with mass

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Homework Help Overview

The discussion revolves around a physics problem involving forces acting on a mass of 6.0 kg. The original poster questions the correct approach to determine the acceleration of the mass given two forces of 3.0 N and 1.0 N.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to find the acceleration using only the 3.0 N force, questioning whether the 1.0 N force should be considered. Some participants inquire about the reasoning behind neglecting the 1.0 N force and discuss the importance of vector addition in determining the net force.

Discussion Status

Participants are exploring the necessity of incorporating both forces into the calculation of net force. There is a focus on understanding vector components and the implications of resolving forces at angles, with no explicit consensus reached yet.

Contextual Notes

Participants note that the forces may not be acting at right angles, which complicates the determination of the resultant force. The original poster's approach is based on a common assumption that may not apply in this scenario.

Hannahj1
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Homework Statement


A force of 3.0 N and 1.0 N act on a 6.0 kg mass as shown. What is the acceleration of the 6.0 kg mass?

Homework Equations


Fnet = ma

The Attempt at a Solution


I did 3N as fnet so fnet=ma, 3=6a and solved for a
i was just wondering if what i did was right and if i need to incorporate the 1N in any way? Thank you
 

Attachments

  • Screen Shot 2015-08-10 at 12.09.34 AM.png
    Screen Shot 2015-08-10 at 12.09.34 AM.png
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Hi, Hannahj1.

Can you give a reason for neglecting the 1.0 N force when finding the net force?
 
TSny said:
Hi, Hannahj1.

Can you give a reason for neglecting the 1.0 N force when finding the net force?

When you find the net force it is usually the hypotenuse of the x and y components and here you're already given the hypotenuse (the 3N)
 
Yes, you do need to incorporate the 1N. Vector addition is necessary in this problem, as both forces have components that contribute to the acceleration of the block. You cannot ignore the 1N.
 
Hannahj1 said:
When you find the net force it is usually the hypotenuse of the x and y components and here you're already given the hypotenuse (the 3N)
That's because you are used to being given problems in which the applied forces are at right angles to each other, so the resultant is the hypotenuse.
But in general, as here, the applied forces can be at any angle to each other. The 3N line is not the hypotenuse of any triangle of interest.

A standard technique is to pick a pair of directions at right angles (vertical and horizontal in the screen shot would be convenient) and resolve each applied force into components in those two directions. Then you can add the components in each direction separately, and finally figure out what the resultant of those two forces is. Here, at last, you will be looking for the hypotenuse.
Do you know how to resolve a force into its components?
 

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