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Physics Fundamentals: Work Done

  1. Jun 30, 2014 #1
    1. The problem statement, all variables and given/known data

    This is a theoretical question that I do not quite fully understand. " An object moving up a 6m ramp to a height of 2m v.s vertically moving an object up 2m." Someone tell me the work done is the same for both scenario. How are they the same? Surely kinetic energy is involved in moving the 6m ramp, am I right?

    2. Relevant equations

    Work done = Force x Distance
    Kinetic Energy = 0.5*mass*velocity^2
    Gravitational Potential Energy = mass*acceleration due to gravity*height

    3. The attempt at a solution

    Can someone explain why moving an object vertically up has the same work done as moving the object up the ramp, both at the same height?
  2. jcsd
  3. Jun 30, 2014 #2


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    Work out force * distance in both cases.

    Assume that the object starts from rest and coasts to a halt at the top in both cases - that allows you to forget about KE.
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