- #1
neoking77
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At a distance H above the surface of a plane, the true weight of a remote probe is one percent less than its true weight on the surface. The radius of the planet is R. Find the ratio H/R.
Work:
Let Mp be mass of planet and Ms be the mass of space probe
(true weight) Ft = GMpM/(r+h)^2
(surface weight) Fs = GMpM/r^2
Ft = GMpMs/r^2 - GMpMs/r^2(0.01)
Ft = GMpMs/r^2 - GMpMs/r^2(0.01) = GMpMs/(r+h)^2
i don't know where to go from here
thanks in advance.
Work:
Let Mp be mass of planet and Ms be the mass of space probe
(true weight) Ft = GMpM/(r+h)^2
(surface weight) Fs = GMpM/r^2
Ft = GMpMs/r^2 - GMpMs/r^2(0.01)
Ft = GMpMs/r^2 - GMpMs/r^2(0.01) = GMpMs/(r+h)^2
i don't know where to go from here
thanks in advance.