Physics Gravitational Force Question

AI Thread Summary
The discussion centers on calculating the ratio H/R, where H is the height above a planet's surface at which a probe's weight is 1% less than its weight on the surface. The equations for true weight (Ft) and surface weight (Fs) are established using gravitational force formulas. The user is advised to manipulate the equations by multiplying both sides by r^2 and rewriting the ratio of distances. The conversation emphasizes simplifying the expression to facilitate further calculations. The thread concludes with a request for additional guidance on completing the problem.
neoking77
Messages
30
Reaction score
0
At a distance H above the surface of a plane, the true weight of a remote probe is one percent less than its true weight on the surface. The radius of the planet is R. Find the ratio H/R.

Work:
Let Mp be mass of planet and Ms be the mass of space probe

(true weight) Ft = GMpM/(r+h)^2

(surface weight) Fs = GMpM/r^2

Ft = GMpMs/r^2 - GMpMs/r^2(0.01)

Ft = GMpMs/r^2 - GMpMs/r^2(0.01) = GMpMs/(r+h)^2

i don't know where to go from here

thanks in advance.
 
Physics news on Phys.org
Multiply both sides by r^2 and write

\frac {r^2}{(r+h)^2}

as

\frac {1}{\left(1 + \frac {h}{r}\right)^2}

You should be able to handle the rest.
 
thank you very much for your help
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top