Physics Help: Calculating μ sub s and μ sub k

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SUMMARY

The discussion focuses on calculating the coefficients of static friction (μ sub s) and kinetic friction (μ sub k) using a practical example involving a 95 kg clock on a horizontal floor. To determine μ sub s, a force of 650N is required to initiate motion, while a force of 560N maintains constant speed, indicating μ sub k. The correct values for μ sub s and μ sub k can be derived from these forces, with μ sub s being less than 650N and greater than 0N, confirming the principles of static friction.

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ItsNoah
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Hi all, I just registered for this forum and I am excited to learn a lot! I am taking physics this year and I am enjoying it a lot although it is quite difficult for me.
Quick question:
how do I calculate μ sub s and μ sub k(formulas would be excellent)?
Thanks!
 
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If you're talking about the coefficients of friction for objects, they are typically determined by experiment.
 
Pengwuino said:
If you're talking about the coefficients of friction for objects, they are typically determined by experiment.

For example: A 95 kg clock initially a trest on a horizontal floor requires a 650N horizontal force to set it in motion. After the clock is in motion, a horitzontal force of 560N keeps it moving with a constant speed. Find μ sub k and μ sub s between the clock and the floor.

I said the μ sub s was < 650N and > 0 N would that be correct since static friction means it's not moving and if it's between 0 and 650 it will be staying at rest?
 

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