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Physics in vertical jump and basball hit
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[QUOTE="haruspex, post: 4985706, member: 334404"] You are trying to calculate a distance given an initial speed and a final speed. You don't know the time, so what else will help? What equations do you know related to collisions? What is or may be conserved? It's a measure of how well bodies rebound from collisions. Take two bodies, initially moving at speeds u1, v1. Positive is to the right, say. Take it all to be in one straight line. After collision, they move off with speeds u2, v2. It turns out that if you were to repeat the experiment with the same bodies at different speeds you would find there is a constant (usually written as e, for elasticity, or R for restitution) such that v2-u2 = R(u1-v1). (Note the sign reversal.) For more info G**gle for coefficient of restitution. In a perfectly elastic collision, the coefficient is 1. The fraction of energy retained is the square of the coefficient. Mass centre up 6 feet - definitely unrealistic. What take-off speed would be needed? What SUVAT equations do you know? (You should have listed these in the OP.) [/QUOTE]
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Physics in vertical jump and basball hit
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