Physics kinematics calculus question

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Homework Help Overview

The discussion revolves around a kinematics problem involving the motion of a particle with an initial acceleration that decreases continuously to half every specified time interval. The original poster seeks to determine the terminal velocity of the particle given that the initial velocity is zero.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to express acceleration as a function of time and consider using geometric progression or differential equations to derive the relationship. There are attempts to relate the problem to concepts of exponential decay.

Discussion Status

Several participants provide insights into the mathematical framework needed to approach the problem, including the use of differential equations and the concept of half-life. There is acknowledgment of the complexity of the topic, with some participants offering guidance on how to derive the necessary expressions.

Contextual Notes

Some participants note the potential confusion regarding the nature of the acceleration's decrease and clarify that the approach may differ based on whether the halving is continuous or discrete. There is also mention of the original poster's unfamiliarity with certain mathematical concepts, such as exponential decay.

shiv_99
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Homework Statement


Initial acceleration of a particle moving in a straight line is a° and initial velocity is zero.
The acceleration reduces continuously to half in every t° seconds. What will be the terminal velocity(v)?

Homework Equations


[itex]\int[/itex]adt=[itex]\int[/itex]dv

The Attempt at a Solution


[itex]^{∞}_{0}[/itex][itex]\int[/itex]adt=[itex]^{v}_{0}[/itex][itex]\int[/itex]dv
(velocity will become terminal only when accelaration becomes 0 and since acceleration is becoming half after every time interval, it will become zero at infinity)
But to use this equation I need to find an expression for acceleration in terms of time. How should i do it? Should i use geometric progression?
 
Last edited:
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a(t) is a decaying exponential - the time to reduce by half is called the "half life".
You can derive the formula if you like ... start with da/dt=λa knowing that a(t°)=a°/2

You should find that the velocity-time graph is asymptotic to some vmax.
 
Last edited:
Hi shiv99, welcome to PF :smile:

shiv_99 said:

Homework Statement


Initial acceleration of a particle moving in a straight line is a° and initial velocity is zero.
The acceleration reduces continuously to half in every t° seconds. What will be the terminal velocity(v)?

Homework Equations


[itex]\int[/itex]adt=[itex]\int[/itex]dv

The Attempt at a Solution


[itex]^{∞}_{0}[/itex][itex]\int[/itex]adt=[itex]^{v}_{0}[/itex][itex]\int[/itex]dv
(velocity will become terminal only when accelaration becomes 0 and since acceleration is becoming half after every time interval, it will become zero at infinity)
But to use this equation I need to find an expression for acceleration in terms of time. How should i do it? Should i use geometric progression?

The final velocity of the particle for the first t seconds is given as [itex]v_1=at[/itex], for the next t seconds is, [itex]v_2= at+at/2[/itex] and so on.

So yes, you can apply the infinite geometric sum for these.
 
Infinitum said:
Hi shiv99, welcome to PF :smile:



The final velocity of the particle for the first t seconds is given as [itex]v_1=at[/itex], for the next t seconds is, [itex]v_2= at+at/2[/itex] and so on.

So yes, you can apply the infinite geometric sum for these.

This would only be correct if the particle's acceleration was halving *discontinuously* every t0 seconds.

The correct approach in this case is to set up a differential equation for a, i.e. [itex]\frac{da}{dt} = -{\lambda}a[/itex] and solve it. Basically, this is the same equation as in exponential radioactive decay.

After integrating (use the conditions given to determine the appropriate bounds), you'll get a closed form expression for a(t).

Now [itex]v(t) = \int_0^t a(t)dt[/itex].

Solve for v(t) and find [itex]\lim_{t \rightarrow \infty} v(t)[/itex] to determine the terminal velocity. The answer should have [itex]\ln 2[/itex] in it.
 
Curious3141 said:
This would only be correct if the particle's acceleration was halving *discontinuously* every t0 seconds.

Ahh, my bad. :blushing:
 
@Infinitum: you had me panicking for a bit there :)
 
Curious3141 said:
This would only be correct if the particle's acceleration was halving *discontinuously* every t0 seconds.

The correct approach in this case is to set up a differential equation for a, i.e. [itex]\frac{da}{dt} = -{\lambda}a[/itex] and solve it. Basically, this is the same equation as in exponential radioactive decay.

After integrating (use the conditions given to determine the appropriate bounds), you'll get a closed form expression for a(t).

Now [itex]v(t) = \int_0^t a(t)dt[/itex].

Solve for v(t) and find [itex]\lim_{t \rightarrow \infty} v(t)[/itex] to determine the terminal velocity. The answer should have [itex]\ln 2[/itex] in it.

Here what will be the value of lambda for this ques. Plz help because this(exponential radioactive decay)is a new concept for me
 
Lambda is a dummy constant - you find out what it is after you solve the differential equation by using the fact that you know one of the solutions, vis: a(t°)=a°/2 ... you'll also get a constant of integration which you find from a(0).
 
But how do you use it find a(t)
 
  • #10
You find a(t) by solving the differential equation provided.

One last time: a(t) is the solution to: [itex]\frac{da}{dt} = \lambda a[/itex] knowing that [itex]a(t=0)=a_0[/itex] and [itex]a(t=T_{1/2})=a_0/2[/itex]

Or you can google "exponential decay" or "radioactive decay" and use the solution provided.
 
  • #11
shiv_99 said:
Here what will be the value of lambda for this ques. Plz help because this(exponential radioactive decay)is a new concept for me

Simon has already covered the essentials. You need to express [itex]\lambda[/itex] in terms of [itex]t_0[/itex] by solving the differential equation, then using the "half-life" condition stated.
 
  • #12
I'm allowing that Shiv may not know how to solve differential equations ... though just looking up the solution and adapting it to this specific case is also valid. It wouldn't be the first time someone was doing a problem without the broader knowledgebase the rest of us take for granted. Nothing wrong with that as such - it shows the ambition and courage of the self taught.
 

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