The speed of a bullet as it travels down the barrel of a rifle toward the opening is given by v=(-5.00x10^7)(t^squared)+(3.00x10^3)(t)... v=m/s, and t=s. Acceleration of the bullet just as it leaves the barrel is 0m/s^squared. Questions is: How do i find the acceleration and position of the bullet as a function of time when the bullet is in the barrel? length of time the bullet is accelerated? the speed at which the bullet leaves the barrel? what is the length of the barrel? that is the complete question: however what i really want to know is what are the actual givens so i can carry out the kinematics? I can't figure out what to take out from what is given to me.