Physics of a TreadWheel [Abstract Concept?]

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SUMMARY

The discussion focuses on the physics of a tread wheel crane, specifically calculating the maximum weight that can be lifted given specific parameters. The outer circle radius is 6m, the inner circle radius is 0.5m, and the user's weight is 500N. Key equations include F = (m)(v^2)/r and a(radial) = (v^2)/r, which are used to analyze the forces acting on the system. The user seeks clarification on the relationship between radial and tangential forces and how to determine the mass in this context.

PREREQUISITES
  • Understanding of basic physics concepts such as force, mass, and acceleration
  • Familiarity with circular motion equations, including centripetal acceleration
  • Knowledge of trigonometric functions to analyze forces in a circular system
  • Ability to apply Newton's laws of motion in practical scenarios
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  • Study the principles of torque and its application in rotating systems
  • Learn about the mechanics of pulleys and their impact on force distribution
  • Explore the concept of angular velocity and its relationship with linear velocity
  • Investigate the historical applications and designs of human-powered cranes
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Students of physics, mechanical engineers, and anyone interested in the mechanics of ancient lifting devices will benefit from this discussion.

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Homework Statement


[EDIT] Cleaned up the problem.

A tread wheel crane is an ancient device used to lift heavy objects. It consists of a large circle (like a hamster wheel) for a person to walk inside. The large circle connects to the middle where there is a small circle that is attached a rope that goes over a pulley and hooks onto some mass.
http://www.lowtechmagazine.com/2010/03/history-of-human-powered-cranes.html

Givens:
Outer circle radius = 6m
Inner circle radius = 0.5m
My weight: 500N
My speed: unknown.
I stand 1.5m away from the center of both circles

What is the maximum weight I can lift?

Homework Equations


F = (m)(v^2)/r
a(radial) = (v^2)/r
a(radial) = (r)(w^2)
v(tang) = (r)(w)

The Attempt at a Solution


I draw the two circles and placd a dot 1.2m from the center on the edge of the outer circle. The distance from the edge to the center is the radius of the big circle.

You can work out that the tangential force is mgsin(theta) given the geometry. Similarily, you can get a force directed outward mgcos(theta)

I'm thinking that F(Radial) is equal to F(outward). But I also thought perhaps you can solve v(tangential) given the tangent force...

But going ahead with the F(Radial) thing,

F(radial) = F(outward)
500cos(theta) = m(v^2)/r

That is where I was able to get to, because I do not know what mass is in this context. Nothing is really spinning around. Maybe my whole approach is wrong. I would greatly appreciate insight and help!
 
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v^2/r is normally associated with centripetal acceleration. What is wanted in this case is the tangental force at the radius of the small circle.
 
Yeah, I figured that after I thought about it a lot.

So F = ma, and we have the tangental force at the radius of the bigger circle.

But f = ma, and once again, we don't have m and we shouldn't even have a. The circle should not be accelerating. The angular velocity anyway.
 
012anonymousx said:
But f = ma, and once again, we don't have m and we shouldn't even have a.
You have the weight that is supposed to be lifted by a rope attached at the radius of the inner wheel.
 

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