1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Physics Practical: Check proportionality

  1. Aug 16, 2015 #1
    1. The problem statement, all variables and given/known data
    image.jpg image.jpg image.jpg

    For part d), how to show that they are inversely proportional to each other ? The mark scheme states:

    "Correct calculation to check inverse proportionality. √h x cosϑ = k. Sensible comments relating to calculations to within 20% or their own value and suggested relation."

    What do they mean by 20%?
    2. Relevant equations
    Percentage uncertainty = (uncertainty/measured value) x100%

    3. The attempt at a solution
    My values are,

    √h = (2.95±0.1) cm, cos θ = 0.50. k1 = 2.95 x 0.50 = 1.475
    √h = (2.30±0.1) cm, cos θ = 0.64, k2 = 2.30 x 0.64 = 1.472

    I calculated the percentage difference of k,
    ((1.475-1.472) /1.472 ) x 100% = 0.2%

    Then I calculated the uncertainty of √h = (0.1 / 2.30) x 100% = 4.3%

    This is the method I followed from a textbook, so what does the 20% in the mark scheme represents ? Hope you all understand what I'm doing here..
     
  2. jcsd
  3. Aug 16, 2015 #2

    mfb

    User Avatar
    2016 Award

    Staff: Mentor

    The square root of a height should not have centimeters as units.

    A 20% uncertainty which the quoted text might suggest would be very large.

    I don't like the way the problem is set up. With just those two measurements, it is not reasonable to draw any conclusions about the relation between h and θ.

    Fun exercise: calculate the height h which allows tilting the bottle by 90 degrees without tipping over. Is this realistic?
     
  4. Aug 17, 2015 #3
    Oh yeah, was not aware, sorry.

    Hmm.. what do you mean tilting the bottle by 90 degrees?
     
  5. Aug 17, 2015 #4

    mfb

    User Avatar
    2016 Award

    Staff: Mentor

    Which height h corresponds to θ=0? Is that realistic?
    What happens if you reduce h a bit more?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Physics Practical: Check proportionality
  1. AS Physics Practical (Replies: 2)

Loading...