Physics- Pressure Problem , help

  • Thread starter J.live
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  • #1
J.live
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Two containers contain the same gas at different temperatures and pressures, as indicated in the figure. The small container has a volume of 1 L, and the large container has a volume of 2 L. The two containers are then connected to each other using a thin tube, and the pressure and temperature in both containers are allowed to equalize. If the final temperature is 321 K, what is the final pressure? Assume that the connecting tube has negligible volume and mass.


Attempt : Pf Vf / 321 =( 3 x 10^5 )(2L) / 600 + (2 X 10^5)(1L) / 200


I am stuck here , can't solve it . I tried solving for the variable didn't get the right answer.


Here is the diagram :
 

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Answers and Replies

  • #2
J.live
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bump :/
 
  • #3
iRaid
559
8
[tex]\frac{(Pf)(V)}{T}[/tex] = [tex]\frac{(P1)(V1)}{T1}[/tex] + [tex]\frac{(P2)(V2)}{T2}[/tex]

Got it from there?
 
  • #4
J.live
95
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Yeah, how do I go about it?
 
  • #5
wheelatharm
13
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Did you use 3L as the final volume.

Looks like you get one eq. w/ one variable.
 

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