Physics problem involving work done by friction

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The discussion focuses on applying the law of conservation of energy to a physics problem involving work done by friction. A clerk pushes a filing cabinet, and the challenge is to determine the cabinet's speed after moving a certain distance while accounting for friction. Participants clarify that the work done by friction should be considered as energy lost, not added to the total energy before. The net force acting on the cabinet is calculated to find the velocity, emphasizing that energy dissipated by friction transforms into heat. The conversation highlights the importance of correctly applying energy conservation principles in problems involving friction.
a seeker
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hi, I am learning about how to solve energy problems using the law of conservation of energy. I am okay with most of the problems, but I am confused about how to solve the ones involving the work done by frictional force. For example:

A clerk pushes a filing cabinet of mass 22.0 kg across the floor by exerting a horizontal force of magnitude 98N. The magnitude of the force of kinetic friction acting on the cabinet is 87N. The cabinet starts from the rest. Use the law of conservation of energy to dertermine the speed of the cabinet after it moves 1.2m.

First, I should state that due to the law of conservation of energy, total energy before=total energy after, which can be restated as:
E applied + W done by friction = E_k
(98*cos0)(1.2)+(87*cos180)(1.2)=1/2(22)(v)^2

but is it right? I know if i do it like this, i get the right answer, but that's the only reason I ended up with the statement, E applied + W done by friction = E_k, after many trials and errors!
Is the W done by friction always included in the "total energy before"? I thought it was supposed to be a part of the "total energy after" cause doesn't friction occur after the object is given some work?
please try to explain this stuff!
 
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First, there is cosine involved since you are directly dealing with a horizontal component. Second the addition is wrong. The frictional force will oppose the movement, so the net force applied on the cabinet is 90N - 87N = 3N. Now since, F_{net}d = \frac{1}{2} v^{2}, you can calculate the velocity.
 
ya, but I am supposed to solve the problem using the concept of conservation of ENERGY! and i know that you can't subtract energy factors.
read what I've asked for.
 
Conservation of energy? I don't see how is that practical. What happens is that the big part the energy (87*1.2 J) given to the cabinet gets dissipated by friction (this energy is transformed into heat between the floor and the surface of the cabinet).
 
a seeker said:
ya, but I am supposed to solve the problem using the concept of conservation of ENERGY! and i know that you can't subtract energy factors.
read what I've asked for.

i believe your approach is sound, giving V^2=1.2 In fact, except for the sequence of algebraic steps, appears to be the same as Wergs (tho he accidentally put 90 instead of 98).
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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