Physics Projectile Launched at Angle. HELP, TEST TODAY IN 2 HOURS! 1. The problem statement, all variables and given/known data An object is launched from the top of a building with an initial velocity of 15 m/s [32 degrees]. If the building is 65.0 m high, how far from the base of the building will the object land? 2. Relevant equations dx = vix (t) dy=viy(t) + 1/2a (t)^2 3. The attempt at a solution First I drew a diagram. Then set up the x and y table: The variables I know; vix= 12.72 (which I got from vicos(theta), viy= 7.948, ay=-9.81, ax=0. Then I solved the time for the 32 degrees. Then I solved the time for the other part and then I solved for dx, I got 66.9 m. The answer in the book says its 58 m. Can't figure out how to do this, help please!!!