(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A particle leaves the origin with initial velocity v0 = 11i+ 14 j m/s. It undergoes a constant acceleration given by a = –1.2 i + 0.26 j m/s2

(a) When [i.e., for t greater than zero] does the particle cross the y axis?

t = s

(b) What is its y coordinate at that time?

y = m

(c) How fast is it moving, and in what direction, at that time?

v = m/s

θv = ° from the +x axis

2. Relevant equations

Integrals Calculus I believe

3. The attempt at a solution

v(t) = ∫ a dt + C = -1.2 t i + 0.26 t j + 11 i + 14 j

x(t) = ∫ vx dt + C1 = -0.6 t^2 + 11 t

y(t) = ∫ vy dt + C2 = 0.13 t^2 + 14 t

a) t=18s

b) y= 300m

c)= 22m/s

d) Can't figure out.... What direction is it moving at that time? ____ degrees

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# Homework Help: Physics question:Particle leaves the origin

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