Physics Questions on Thrown Up Ball & Bullet

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Homework Help Overview

The discussion revolves around two physics problems involving projectile motion: one concerning a ball thrown upwards and the other about a bullet shot straight up. Participants are exploring the calculations related to maximum height and initial speed based on given parameters.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to calculate the maximum height of a thrown ball and the initial speed of a bullet using kinematic equations. Some participants question the validity of the equations used and the assumptions made regarding final and initial velocities.

Discussion Status

Participants are actively engaging with the problems, offering different interpretations and calculations. There is a mix of agreement and questioning regarding the methods used, particularly in the second problem about the bullet's speed. Some guidance has been provided, but no consensus has been reached.

Contextual Notes

Participants reference classroom teachings about projectile motion, specifically the relationship between upward and downward speeds. There is also mention of homework constraints and the need for clarification on the kinematic equations involved.

A.I. BOT
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[Solved] Thrown up ...

I am stupid when it comes to Physics so please guide me :). I have 2 questions on a worksheet I got today and I am stuck.

A ball is thrown up with a speed of 30 m/s. What is the maximum height reached by the ball?
a) 23m b) 46m c) 92m d) 132m
Is it b? .. (30 m/s) / 9.8 m/s^2 = 3.06s ... 30 x 1/2(3.06) = 46m?

A bullet is shot stright up and returns to its starting point in 10 s. What is the initial speed of the bullet
a) 9.8 m/s b) 25 m/s c) 49 m/s d) 98 m/s
Is it b? .. Vi = Vf - a*1/2(t) ... Vi = 0, Vf = 0, a = 9.8, t = 1/2(10) = 5 ... Vi = 0 - 9.8*1/2(10) ... 25m?

Thanks :)
 
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The first answer looks to be correct (not sure what the 2nd part is you used to find it), but I get something different on your second question.

"Vi = Vf - a*1/2(t)"

Are you sure there's a 1/2 there? http://en.wikipedia.org/wiki/Kinematic
 
Hmm your right, so it should be d) 98 m/s I am assuming ?
 
A.I. BOT said:
Hmm your right, so it should be d) 98 m/s I am assuming ?
How does the final velocity at the end of 10 seconds compare to the initial velocity?
 
I was told in school that when something is thrown up ... the speed it went up, will be the same speed coming down. The bullet is going to return to it's start point it states, thus making its final velocity 0m/s ? so ... If I just plug the numbers into Vi = Vf - at I get 98m/s, so I will go with that and see what it says when I get the assignment back.

Thanks for the help guys :)
 
A.I. BOT said:
I was told in school that when something is thrown up ... the speed it went up, will be the same speed coming down. The bullet is going to return to it's start point it states, thus making its final velocity 0m/s ? so ... If I just plug the numbers into Vi = Vf - at I get 98m/s, so I will go with that and see what it says when I get the assignment back.

Thanks for the help guys :)
Your statement is contradictory. The speed is the same when it gets back to the starting point that it had when thrown. That is not zero. If it were zero, it would never have gone up.
 

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