Physics: Specific heat capacity of a solid

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Homework Help Overview

The discussion revolves around the specific heat capacity of a one-dimensional system of microscopic objects modeled with springs. Participants explore the implications of quantum energy levels and the calculation of entropy for varying quanta, as well as the average absolute temperature and heat capacity at different energy states.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the calculation of heat capacity using the classical limit and question the application of the formula involving the Boltzmann constant. There is exploration of whether to multiply by the number of objects or consider the dimensionality of the system.

Discussion Status

Several participants have shared their attempts and reasoning, with some expressing uncertainty about the correct approach to calculating the heat capacity. There is an acknowledgment of differing interpretations regarding the application of constants based on the system's dimensionality.

Contextual Notes

Participants note the challenge of applying classical physics concepts to a small system, emphasizing the limitations of the high-temperature approximation in this context.

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Homework Statement


The diagram below shows a one-dimensional row of 5 microscopic objects each of mass 410-26 kg, connected by forces that can be modeled by springs of stiffness 26 N/m (so each object can be modeled as if it were connected to a single spring of effective stiffness 4ks = 104 N/m -- neglect any possible differences for objects near the ends). These 5 objects can move only along the x axis.Use these precise values for the constants:
hbar = 1.054610-34 J · s (Planck's constant divided by 2)
k = 1.380710-23 J/K (the Boltzmann constant)What is one quantum of energy for one of these objects?
Delta E = 5.37743e-21 correct check mark J

Using the Einstein model, calculate the entropy of this system for total energy of 0, 1, 2, 3, 4, and 5 quanta.
q = 0: S = 0 correct check mark J/K

q = 1: S = 2.22215e-23 correct check mark J/K

q = 2: S = 3.73900e-23 correct check mark J/K

q = 3: S = 4.90887e-23 correct check mark J/K

q = 4: S = 5.86590e-23 correct check mark J/K

q = 5: S = 6.67745e-23 correct check mark J/K

Calculate to the nearest degree the average absolute temperature of the system when the total energy is in the range from 3 to 4 quanta. (You can think of this as the temperature when there would be 3.5 quanta of energy in the system, if that were possible.)
T3 to 4 = 561.88730 correct check mark K

Calculate to the nearest degree the average absolute temperature of the system when the total energy is in the range from 4 to 5 quanta. (You can think of this as the temperature when there would be 4.5 quanta of energy in the system, if that were possible.)
T4 to 5 = 662.61229 correct check mark K

Calculate the heat capacity per object when the total energy is 4 quanta. (Think of this in terms of increasing from 3.5 quanta of energy in the system to 4.5 quanta of energy in the system, if that were possible.)
C4 = 1.067745e-23 correct check mark J/K/object

If the temperature were raised very high, classically what would we expect the heat capacity per object to be for this one-dimensional system? Give a numerical value.
Chigh T = ? wrong check mark J/K/object
(One reason for the discrepancy is that the high-temperature limit assumes that the number of oscillators is large (N >> 1), which is not the case in this tiny system.)

Homework Equations



C= deltaE/deltaT

classical limit of 3k = 4.210-23 J/K/atom

The Attempt at a Solution



I got all the questions except the last one which I've already tried searching for clues in the internet.
I tried 3kN= 3*1.380710e23*5 but got it wrong.
I thought it was just supposed to be 3k like in the relevant equation but that's wrong maybe because N=5??
I also thought that 3 in the 3k equation has something to do with 3 springs, so I tried 2*k instead of 3*k but got it wrong too.
Please help.
 
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I don't think you need to multiply it by 5 if you're already multiplying by 3. Since you do 3k for a three-dimensional system, i figured that you could just do 2k, since only two springs are attached to each 'atom'. This was also wrong. I also tried 5k, but that didn't work. Apparently 3k is also wrong.

Now that we've eliminated 5 options, anyone else have ideas?
 
I didn't know that 3k was for a three-dimensional system. If that's the case, then how about trying 1k since this is a one-dimensional system.

Ok. I got the answer. The answer is 1k= 1.3807e23.

Thanks for joining the discussion, phys2211. And Thanks a lot for that important point you gave out.
 
glad i could be of service :)
 
Hey how do u search for T3 to 4 on T4 to 5?
Thanks
 

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