Physics student in need of some help

Click For Summary
A physics student is struggling with linear motion problems, particularly in understanding how to approach questions that require additional calculations beyond the immediate query. They provided a specific problem involving the speed of a cockroach and their own movement toward it, expressing confusion over initial and final velocities. The discussion clarifies that the man's initial velocity is indeed 0.80 m/s, and emphasizes the importance of using the correct distance and time in the relevant equations. Participants suggest focusing on the total distance the person must cover and the time it takes for the cockroach to reach safety. This exchange highlights common challenges faced by students in applying physics concepts to problem-solving.
nyguy
Messages
2
Reaction score
0
I'm fairly new here and I was in search of some help to clarify some problems. I know that it may sound very easy to most on this forum but I seem to be having a tough time with straight-line (linear) motion problems. When being asked specific questions in a problem I notice that one has to go beyond what's originally being asked of you. For example, I might be asked to find the acceleration, but I might need to find the time to help solve the puzzle. Also, problems dealing with the acceleration of two bodies can really get to me as well. Here is an example of a problem that I took straight out of my textbook. Please help:

Large cockroaches can run as fast as 1.50m/s in short bursts. Suppose you turn on the light in a cheap motel and see one scurrying directly away from you at a constant 1.50m/s as you move toward it at 0.80m/s. If you start 0.90m behind it, what minimum constant acceleration would you need to catch up with it when it has traveled 1.20m, just short of safety under a counter?

I was having problems determing if 0.80m/s was the man's initial velocity or the final velocity when he turned on the light. Also, 0.90m threw me off a bit. Please help and thanks in advance.
 
Physics news on Phys.org
0.8 m/s is the man's initial velocity, it seems to be a straightforward application of the equation relating distance and acceleration:
\[<br /> d = v_0 + {\textstyle{1 \over 2}}at^2 <br /> \]

-t will be the time it takes the cockroach to reach its shelter
-distance will be the distance the person needs to travel (.9m+1.2m)
-initial velocity is 0.8 m/s
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 4 ·
Replies
4
Views
4K
Replies
18
Views
2K
  • · Replies 16 ·
Replies
16
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 98 ·
4
Replies
98
Views
6K
  • · Replies 9 ·
Replies
9
Views
1K
Replies
14
Views
2K
Replies
3
Views
5K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K