Physics- velocity/ distance problem?

In summary, to find the velocity of an object starting from rest with an acceleration given by a = Bt^2 − 1/2Ct, where B = 4.5 m/s^4 and C = −2.2 m/s^3 after 7.5 seconds, we need to integrate the equation with respect to time, substitute the given values for B and C, and then substitute t=7.5s to get the velocity. Similarly, to find the distance traveled after t=7.5s, we need to integrate the equation with respect to time and substitute the given value for t to get the distance.
  • #1
J.live
95
0

Homework Statement



An object starts from rest and has an acceleration given by
a = Bt^2 − 1/2Ct, where B = 4.5 m/s^4 and C = −2.2 m/s^3

(1) What is the object's velocity after 7.5 s? (Indicate the direction with the sign of your answer.)

(2) How far has the object moved after t = 7.5 s?


Homework Equations



v=at


The Attempt at a Solution



I integrated the equation its not coming out right

what am i doing wrong?

If someone can kindly explain.

Here is the attachment
 

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  • #2
Hint
v=at is valid if acceleration is not time dependent (i.e. it is constant)
 
  • #3
So, I am using the wrong equation? What equation should i use?
 
  • #4
you have to integrate the equation not differentiate
 
  • #5
So i have to integrate a= Bt^2- 1/2Ct?

Do i substitute the answer in equation v=at? Or i can't use that equation at all since a is time dependent.

Can you show some work so I have a better idea?
 
Last edited:
  • #6
We derive the equation v=u+at assuming that acceleration is constant.
here acceleration is time dependent
dv/dt = a
dv=adt
substitute a with the equation you have
integrate both sides of the equation with limits 0 to v and 0 to t respectively
after this you get an equation of v as a funtion of time.
substitute t=7.5s in this equation to get velocity at that time.
 

1. What is the formula for calculating velocity in physics?

The formula for calculating velocity in physics is velocity = distance / time, or v = d/t. This formula is used to determine the speed and direction of an object's motion.

2. How is distance calculated in a velocity/ distance problem?

Distance can be calculated by multiplying the velocity of an object by the time it has been in motion. For example, if an object has a velocity of 50 meters per second and has been in motion for 5 seconds, the distance traveled would be 250 meters.

3. What is the difference between speed and velocity?

Speed is a measure of how fast an object is moving, while velocity is a measure of both speed and direction. This means that an object can have the same speed but different velocities if it is moving in different directions.

4. How does acceleration affect velocity in a distance problem?

Acceleration is the rate at which an object's velocity changes. In a distance problem, acceleration can either increase or decrease the velocity of an object, depending on its direction. For example, if an object is accelerating in the same direction as its velocity, it will increase in speed. However, if it is accelerating in the opposite direction, it will decrease in speed.

5. What are the units used to measure velocity and distance in physics?

Velocity is typically measured in units of meters per second (m/s). Distance can be measured in various units, such as meters, kilometers, or miles, depending on the scale of the problem. It is important to use consistent units when solving a velocity/ distance problem to ensure accurate calculations.

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