- Homework Statement
- Here is another exercise focusing on how the distance, or gap, between two objects changes over time. If a taxi is racing toward you from the north at 3/4 light speed, and another taxi is racing toward you from the south at 1/2 light speed, how quickly from your perspective is each taxi approaching the other?
- Relevant Equations
- d = vt
The answer is tD = [D_0 - 3/4ct - 1/2ct] I just have 2 questions.
I realize for 2 vectors approaching it is negative for distance and for velocity positive. What be the rule for time? How do I find vector answers for velocity and distance and time?
I am confused why I have "td = ..." ? Can someone explain? "td" doesn't even make sense.