Picture Posting Help - Tips & Tricks

[G Lenny]

Help with the picture posted!

 

[isukatphysics69]

Is there an angle given? if not, maybe use those tiny dots and create a triangle and take the tangent inverse to find the angle. Then break the problem up into its x and y components

 

[G Lenny]

Is there an angle given? if not, maybe use those tiny dots and create a triangle and take the tangent inverse to find the angle. Then break the problem up into its x and y components

There is no angle give, everything that I have is in the picture.

 

[isukatphysics69]

Yes so i haven't looked closely but if those tiny dots are equivalent distances i.e 1 unit each then try finding the angle using the tangent inverse after creating a triangle somewhere.

 

[isukatphysics69]

Then you can create your x and y components

 

[G Lenny]

Yes so i haven't looked closely but if those tiny dots are equivalent distances i.e 1 unit each then try finding the angle using the tangent inverse after creating a triangle somewhere.

Alright. I got 114 for the whole bottom and 46 for the height. The max height would be at 114/2=57. Arctan(46/57)=38.904deg

 

[G Lenny]

Yes so i haven't looked closely but if those tiny dots are equivalent distances i.e 1 unit each then try finding the angle using the tangent inverse after creating a triangle somewhere.

How would I go about finding gravitational acceleration with an angle and initial velocity?

 

[Nathanael]

Alright. I got 114 for the whole bottom and 46 for the height. The max height would be at 114/2=57. Arctan(46/57)=38.904deg

That’s the angle from origin to peak, not the same as initial angle.

Anyway I wouldn’t do it that way. I would say pretend the initial angle θ and gravity strength g are known, then answer two questions: What is the max height in terms of θ and g? What is the final position in terms of θ and g?
If you can solve those two questions, then equate them with 46 and 114 meters, then you will have two equations in two unknowns (θ and g) and so can solve for g.

 

[isukatphysics69]

How would I go about finding gravitational acceleration with an angle and initial velocity?

hint: gravity points down use your coordinate axis and break up components

 

[G Lenny]

That’s the angle from origin to peak, not the same as initial angle.

Anyway I wouldn’t do it that way. I would say pretend the initial angle θ and gravity strength g are known, then answer two questions: What is the max height in terms of θ and g? What is the final position in terms of θ and g?
If you can solve those two questions, then equate them with 46 and 114 meters, then you will have two equations in two unknowns (θ and g) and so can solve for g.

I can't think what equations would give me max height in terms of theta and g and final position in terms of theta and g.

 

[berkeman]

This thread is wrong in several ways:

• Threads posted in the Homework Help forums need to follow the HH rules.
  
• That means that the OP (original poster) needs to post using the HH Template they are provided and fill it out, showing the Relevant Equations and showing their Attempt at the Solution
• Without a Template filled out showing the effort of the poster to try to solve the problem, it is against the PF rules to provide help. Please "Report" such OPs with no effort shown. Please do not respond with help.

@G Lenny -- check your private messages in a few minutes...

 

[berkeman]

@G Lenny -- Please re-post and fill out the Template that you are provided when starting a new schoolwork thread. This includes the sections on the Relevant Equations, and your Attempt at a Solution. Thank you.