Piecewise does not translate properly

  • Thread starter Thread starter dumguy
  • Start date Start date
Click For Summary
SUMMARY

The discussion centers on a piecewise-defined function describing the distance traveled by a car approaching a school bus with an extended stop sign. The car travels at a constant velocity of 18 m/s for the first 0.75 seconds, followed by a deceleration modeled by the equation d = -3t² + 22.5t - 1.6875 for the next 3 seconds. The user identifies a contradiction in the initial velocities of 18 m/s and 22.5 m/s, leading to confusion about the car's stopping distance, which they calculate as 53.3125 meters. The discussion highlights inconsistencies in the problem setup and suggests that translating the parabola may yield a more accurate representation of the car's motion.

PREREQUISITES
  • Understanding of piecewise functions
  • Familiarity with basic kinematics equations
  • Knowledge of graphing techniques for quadratic functions
  • Ability to analyze and resolve mathematical contradictions
NEXT STEPS
  • Study piecewise function applications in physics
  • Learn about kinematic equations and their derivations
  • Explore graphing techniques for quadratic equations
  • Investigate methods for resolving mathematical inconsistencies in problem statements
USEFUL FOR

Students in physics or mathematics, educators teaching kinematics, and anyone interested in understanding piecewise functions and their applications in real-world scenarios.

dumguy
Messages
12
Reaction score
0
1. Homework Statement [/b]A car is driving at a constant velocity of 18 m/s. There is a school bus on the road with its stop sign extended. The car is 40 metres away from the bus when the driver sees the stop sign.
There is a time delay of 0.75 secondsbetween the time the driver sees the sign and when the driver can begin to slow down. This is called the "driver reaction time". During this reaction time the distance d, in m, traveled by the car is given by the equation d=18t, where t is the time in seconds from when the driver sees the bus. When brakes are applied, after the 0.75 second reaction time, the distance d traveled by the car in time t is given by the equation d=-3t^2+22.5t-1.6875. After the brakes are applied it takes 3 seconds for the car to come to a stop. These 3 seconds plus the 0.75 second driver reaction time means the car stops 3.75 seconds after seeing the school bus.
i) Write a piecewise-defined function to describe the distance traveled by the car until it stops.iv)how far does the car travel befor it stops?Explain how you found this.

d=(18t, 0<=t<=0.75
(-3t^2+22.5t-1.6875, 0.75<t<=3.75

When I solve the equations individually and add them together, I get 13.5+38.8125=53.3125
When I graph the piecewise on graphing calculator, I get a graph with an end coordinate of
(3.75, 40.5). How is this possible and which one is correct?
 
Physics news on Phys.org
I don't know anything about the graphing solution, but there is something odd about this problem. The formula d=18t says that the initial speed is 18 m/s. But the second term of d=-3t^2+22.5t-1.6875 says that the initial velocity is 22.5 m/s, a contradiction. The -1.6875 doesn't make any sense. If you use the acceleration of -3 from an initial speed of 22.5, you get a deceleration time of 7.5 s, not 3 s. The question has conflicts in it so it is not surprising that different methods result in different answers.
 
perhaps if i translate the parabola up 13.5 units and right 0.75 units we can get a better result. Something is lost in the translation from 2 individual functions to a piecewise. Any ideas are welcome and appreciated.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
4
Views
3K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 3 ·
Replies
3
Views
5K
Replies
1
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
5K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
2
Views
1K