Planck Time Problem: Calculation & Explanation

Click For Summary
The discussion revolves around understanding Planck time, a fundamental concept in physics that signifies the earliest moments of the universe. Participants are trying to find a combination of three constants—speed of light (c), gravitational constant (G), and Planck's constant (h)—to derive a time measurement. One user attempts to combine G and h but initially ends up with incorrect units, indicating a need for further calculation to isolate seconds. The conversation highlights the confusion faced by beginners in physics, particularly in applying fundamental constants to derive meaningful results. Clarification and guidance on the correct approach to the problem are sought.
Sagari
Messages
2
Reaction score
0

Homework Statement



Hi Guys,
Just started a Mechanical Engineering Course and in my Physics this came up, I'm really confused and don't know were to start. I was wondering if anyone could shed any light on the subject. Thanks guys.

Three of the fundamental constants of physics are the speed of light, c = 3.0 × 10⁸ m/s, the universal gravitational constant, G = 6.7 × 10ˉ¹¹m³·kgˉ¹·sˉ², and Planck’s constant,
h = 66 × 10ˉ³⁴kg·m²·sˉ¹.
Find a combination of these three constants that has the dimensions of time. The time is called Planck time and represents the age of the universe before which the laws of physics as presently understood cannot be applied.
Using the formula for the Planck time derived in part (a), what is the time in seconds?

Homework Equations



The Attempt at a Solution

 
Physics news on Phys.org
Sagari said:

Homework Statement



Hi Guys,
Just started a Mechanical Engineering Course and in my Physics this came up, I'm really confused and don't know were to start. I was wondering if anyone could shed any light on the subject. Thanks guys.

Three of the fundamental constants of physics are the speed of light, c = 3.0 × 10⁸ m/s, the universal gravitational constant, G = 6.7 × 10ˉ¹¹m³·kgˉ¹·sˉ², and Planck’s constant,
h = 66 × 10ˉ³⁴kg·m²·sˉ¹.
Find a combination of these three constants that has the dimensions of time. The time is called Planck time and represents the age of the universe before which the laws of physics as presently understood cannot be applied.
Using the formula for the Planck time derived in part (a), what is the time in seconds?

Homework Equations



The Attempt at a Solution


If you multiply G by h, the units are (m³·kgˉ¹·sˉ²) x (kg·m²·sˉ¹)

this gives

kg0·m5·sˉ3

which isn't seconds, but at least the kg has gone!

Use the right amount of the quantities and you will be left with just seconds, presumably.

EDIT: there was no real reason why I chose G and H to start with - but I had to chose a couple of them to show what happens.
 
PeterO said:
If you multiply G by h, the units are (m³·kgˉ¹·sˉ²) x (kg·m²·sˉ¹)

this gives

kg0·m5·sˉ3

which isn't seconds, but at least the kg has gone!

Use the right amount of the quantities and you will be left with just seconds, presumably.

EDIT: there was no real reason why I chose G and H to start with - but I had to chose a couple of them to show what happens.

Ok mate thanks for the help
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
Replies
8
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 15 ·
Replies
15
Views
5K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 5 ·
Replies
5
Views
813
  • · Replies 25 ·
Replies
25
Views
4K
  • · Replies 15 ·
Replies
15
Views
3K
Replies
6
Views
3K
  • · Replies 47 ·
2
Replies
47
Views
2K