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Planck's assumption and Uncertainty principle

  1. Feb 26, 2010 #1
    Hi guys,

    I earned that

    [tex] \Delta E \Delta t \gtrapprox \frac{\hbar}{2} [/tex]

    But one thing that's really strange is, according to Planck's assumption on black-body radiation problem, it just say that energy of each osciliator can be written as

    [tex]E = nhf[/tex]

    where n is an integer. (I hope this would be true)

    So, my question is that if we can measure the energy of an osciliator precisly enough so that Energy of a certain osciliator can meet this inequality.

    [tex](n - 1)hf < E < (n+1)hf[/tex]

    At the same time, we can measure [tex] \Delta t[/tex] in some way but it won't be [tex]\infty[/tex] cause [tex] \Delta E[/tex] is obviously not 0.
    But here is the problem, we can actually know the energy of osciliator because the energy of it have to be multiple of n. So, E is nhf, and we can get the [tex] \Delta t[/tex] not an infinity value which is not reasonable. Because if we measure the energy of an object, the uncertainty of t have to be infinite.

    So, what is the problem?

    I'm not good at eng though :(
  2. jcsd
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