- #1
fab13
- 318
- 6
I have seen that the more a particle has a high energy, i.e ##E##, the more its lifetime is short, respecting so the uncertainty principle.
But by the definition of this uncertainty principle :
##E\,\Delta t \geq \dfrac{\hbar}{2}##, I can write :
##\Delta t \geq \dfrac{\hbar}{2E}##, then ##\Delta t## has a lower limit and not an upper limit.
If this was a upper limit, this would mean that ##\Delta t##, i.e. the apparition time, should be observed in a time interval lower than ##\dfrac{\hbar}{2E}## : for example, if a detector had a time resolution greater than ##\dfrac{\hbar}{2E}##, the particle could not be detected, could it ?
So in which case can we write : ##\Delta t \leq \dfrac{\hbar}{2E}## ??
It seems that I have confusions with this principle.
Any clarification is welcome
But by the definition of this uncertainty principle :
##E\,\Delta t \geq \dfrac{\hbar}{2}##, I can write :
##\Delta t \geq \dfrac{\hbar}{2E}##, then ##\Delta t## has a lower limit and not an upper limit.
If this was a upper limit, this would mean that ##\Delta t##, i.e. the apparition time, should be observed in a time interval lower than ##\dfrac{\hbar}{2E}## : for example, if a detector had a time resolution greater than ##\dfrac{\hbar}{2E}##, the particle could not be detected, could it ?
So in which case can we write : ##\Delta t \leq \dfrac{\hbar}{2E}## ??
It seems that I have confusions with this principle.
Any clarification is welcome