Platinum ion electron configuration

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SUMMARY

The electron configuration of platinum is [Xe] 4f14 5d8. This configuration indicates that platinum, a transition metal in the 6th period, has a filled 4f subshell with 14 electrons and 8 electrons in the 5d subshell. The presence of 4f14 instead of 4f7 is due to the stability provided by the fully filled f-orbitals. A neutral platinum atom contains a total of 78 electrons, corresponding to its atomic number.

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  • Understanding of electron configurations and atomic structure
  • Familiarity with periodic table trends, particularly in transition metals
  • Knowledge of subshell filling order and Hund's rule
  • Basic principles of atomic neutrality and charge balance
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  • Research the significance of electron configurations in transition metals
  • Explore the role of f-orbitals in chemical properties of lanthanides and actinides
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  • Investigate the implications of electron configurations on the reactivity of platinum
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Homework Statement
Write the electron configuration for platinum ion in Pt(NH3)2Cl2.
Relevant Equations
electron configuration
The answer is [Xe] 4f14 5d8. Why does platinum (and other 6th and 7th period d-block elements) have 4f14 instead of 4f7? Thanks.
 
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How many electrons does your configuration have? How many does a platinum atom need to be neutral?
 

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