Chemistry Platinum ion electron configuration

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Platinum's electron configuration is [Xe] 4f14 5d8, which reflects its position in the periodic table as a transition metal. The presence of 4f14 indicates that all 4f orbitals are filled, which is a characteristic of lanthanides and actinides. This configuration results in a total of 78 electrons, which is necessary for a neutral platinum atom. The discussion highlights the stability of filled f-orbitals in heavier transition metals, explaining why platinum does not have a configuration of 4f7. Understanding these configurations is crucial for grasping the behavior of d-block elements.
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Homework Statement
Write the electron configuration for platinum ion in Pt(NH3)2Cl2.
Relevant Equations
electron configuration
The answer is [Xe] 4f14 5d8. Why does platinum (and other 6th and 7th period d-block elements) have 4f14 instead of 4f7? Thanks.
 
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How many electrons does your configuration have? How many does a platinum atom need to be neutral?
 
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