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Please can you help me to resolve this vector force?

  • Thread starter slingboi
  • Start date
  • #1
8
0
A force P is 20N in a direction N 60(degrees) E. What is the resolved part of the force
(a) north
(b) east
(c) N 30(degrees) E

I have an idea of what to do for a and b but can you please show me your working aswell, thanks
 

Answers and Replies

  • #2
ehild
Homework Helper
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Sorry, you need to show your work first.


ehild
 
  • #3
8
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north = 20Cos(60) = 10
east = 20Sin(60) = 17.3
What could (c) be, does N 30(degrees) E become the hypotenuse?
 
  • #4
993
13
(a) & (b) are correct.
 
  • #5
ehild
Homework Helper
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1,803
north = 20Cos(60) = 10
east = 20Sin(60) = 17.3
What could (c) be, does N 30(degrees) E become the hypotenuse?
See attached figure. You need the projection of the force on the direction N 30° E. What is the angle between the force and the given direction?

ehild
 

Attachments

  • #6
8
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30 degrees, oh I see now so would the force N 30(degrees) E be 20cos(30)?
 
  • #7
ehild
Homework Helper
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I hope so ....

ehild
 

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