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Please can you help me to resolve this vector force?

  1. Dec 19, 2011 #1
    A force P is 20N in a direction N 60(degrees) E. What is the resolved part of the force
    (a) north
    (b) east
    (c) N 30(degrees) E

    I have an idea of what to do for a and b but can you please show me your working aswell, thanks
     
  2. jcsd
  3. Dec 19, 2011 #2

    ehild

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    Sorry, you need to show your work first.


    ehild
     
  4. Dec 20, 2011 #3
    north = 20Cos(60) = 10
    east = 20Sin(60) = 17.3
    What could (c) be, does N 30(degrees) E become the hypotenuse?
     
  5. Dec 20, 2011 #4
    (a) & (b) are correct.
     
  6. Dec 21, 2011 #5

    ehild

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    See attached figure. You need the projection of the force on the direction N 30° E. What is the angle between the force and the given direction?

    ehild
     

    Attached Files:

  7. Dec 21, 2011 #6
    30 degrees, oh I see now so would the force N 30(degrees) E be 20cos(30)?
     
  8. Dec 21, 2011 #7

    ehild

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    I hope so ....

    ehild
     
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