Please can you help me to resolve this vector force?

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Homework Help Overview

The discussion revolves around resolving a vector force of 20N directed N 60 degrees E into its components, specifically focusing on the north, east, and a third direction of N 30 degrees E.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the resolved components of the force in the north and east directions, with some attempting to calculate these values using trigonometric functions. Questions arise regarding the projection of the force in the direction of N 30 degrees E and the relationship between this direction and the original force.

Discussion Status

Some participants have provided calculations for the north and east components, while others are exploring how to approach the projection onto the N 30 degrees E direction. There is an ongoing dialogue about the angles involved and the implications for the calculations.

Contextual Notes

There is a request for participants to show their working, indicating a focus on understanding the process rather than just obtaining answers. The discussion also reflects a collaborative effort to clarify assumptions about the angles and components involved.

slingboi
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A force P is 20N in a direction N 60(degrees) E. What is the resolved part of the force
(a) north
(b) east
(c) N 30(degrees) E

I have an idea of what to do for a and b but can you please show me your working aswell, thanks
 
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Sorry, you need to show your work first. ehild
 
north = 20Cos(60) = 10
east = 20Sin(60) = 17.3
What could (c) be, does N 30(degrees) E become the hypotenuse?
 
(a) & (b) are correct.
 
slingboi said:
north = 20Cos(60) = 10
east = 20Sin(60) = 17.3
What could (c) be, does N 30(degrees) E become the hypotenuse?

See attached figure. You need the projection of the force on the direction N 30° E. What is the angle between the force and the given direction?

ehild
 

Attachments

  • resolving.JPG
    resolving.JPG
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30 degrees, oh I see now so would the force N 30(degrees) E be 20cos(30)?
 
I hope so ...

ehild
 

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