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## Homework Statement

A skier starts from rest at the top of a 26 degree slope 1.3Km long.

how long does it take to reach the bottom? (no friction)

**The attempt at a solution**

m=mass

m*g*sin(24) = ma(at slope direction)

divide both side by m

we got

g*sin(24)=a

then use

v^2(final) = V^2(initial)+2(9.8m/s^2)(sin(24))(1300m)

V^2(final) = 0+2(9.8m/s^2)(sin(24))(1300m) we know that initial v is zero.

we get V from the equation above.

then use

v= v(initial)+at

v=0+(9.8m/s^2)sin(24)t

t=V/9.8sin(24).

done!