1. The problem statement, all variables and given/known data A skier starts from rest at the top of a 26 degree slope 1.3Km long. how long does it take to reach the bottom? (no friction) The attempt at a solution m=mass m*g*sin(24) = ma(at slope direction) divide both side by m we got g*sin(24)=a then use v^2(final) = V^2(initial)+2(9.8m/s^2)(sin(24))(1300m) V^2(final) = 0+2(9.8m/s^2)(sin(24))(1300m) we know that initial v is zero. we get V from the equation above. then use v= v(initial)+at v=0+(9.8m/s^2)sin(24)t t=V/9.8sin(24). done!