- #1

defdek

- 12

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The original question:

2 steel rods and copper each of 20mm diameter together support a load of 20 kN. Find the stresses in the rod. Take E for steel and copper as 2.05 GN/m^2 and 1.10 GN/m^2.

l=FL/AE

for steel

l=(20kN)(2m)/(0.0003141x3)(2.05 GN/m^2)=0.021

stress= lE/L=(0.021m)(2.05 GN/m^2)/2m=21525000

and should i do the same for copper?

2 steel rods and copper each of 20mm diameter together support a load of 20 kN. Find the stresses in the rod. Take E for steel and copper as 2.05 GN/m^2 and 1.10 GN/m^2.

l=FL/AE

for steel

l=(20kN)(2m)/(0.0003141x3)(2.05 GN/m^2)=0.021

stress= lE/L=(0.021m)(2.05 GN/m^2)/2m=21525000

and should i do the same for copper?