How Do You Calculate Load Current Values in a Center-Tap Full Wave Rectifier?

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SUMMARY

The discussion focuses on calculating load current values in a center-tap full wave rectifier. Key calculations include determining the Peak, Average, and RMS values of load current, as well as the ripple factor and efficiency. The poster struggles with finding the value of Im, which is essential for these calculations. The absence of a smoothing capacitor is also noted, prompting questions about its impact on the ripple factor.

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snehil31
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Homework Statement
In a centre-tap full wave rectifier shown in the figure, forward resistance of each diode is 50 Ω .

Solve for
i) Peak, Average, RMS value of load current
ii) Ripple factor
iii) Efficiency
Relevant Equations
I(avg) = (2Im/pi) , I(RMS) = Im/(root 2)
[New poster has been reminded by the Mentors to show their work on schoolwork problems]

I have tried many times to solve this problem, but can't understand how to get the value of Im and hence cannot find the Peak & other values of the load current. Please help me to solve and find the Peak, Average, RMS value of load current as well as ripple factor and efficiency of the centre-tap full wave rectifier.

Note:- The figure is attached below.

4.png
 
Last edited by a moderator:
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snehil31 said:
I have tried many times to solve this problem
Could you show us some of that work? Also, without any smoothing capacitor, what do you think the Ripple Factor will be?
 

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