1. Nov 12, 2007

### ijaz

1. The problem statement, all variables and given/known data

How much water at 82 degrees celsius must be added to 1.00kg of water at 14 degrees celsius to give it a final temperature of 36 degrees celsius

2. Relevant equations

qgained=-qlost???????

3. The attempt at a solution

2. Nov 12, 2007

### Bob3141592

If added 1 kg of water at 16 degress to the 1 kg of water at 14 degrees, what would you expect the temperature of the resulting 2 kg of water to be?

Last edited by a moderator: Nov 12, 2007
3. Nov 12, 2007

### mgb_phys

Suppose it takes X joules of energy to raise 1Kg of water 1 degree.
You need to increase 1Kg of water by 36-14 = 22 degrees.
You are going to do this by adding water that is 82-14 = 68 degrees hotter.
Then it's just a matter of ratios.

Suppose you added 1Kg it would end up at half way between 14 and 86 = 14 + (86-14)/2 = 50deg so you need less than 1kg

4. Nov 12, 2007

### steven10137

$$m_1 c_1 \left( {T_1 - T_F } \right) = m_2 c_2 \left( {T_F - T_2 } \right)$$