Please helpppppppppppppppppppppppppppp

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Homework Help Overview

The discussion revolves around a thermal equilibrium problem involving the mixing of water at different temperatures. The original poster seeks assistance in determining the amount of hot water needed to achieve a specific final temperature when mixed with cooler water.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the concept of heat transfer and energy balance, questioning how to set up the equations correctly. There are attempts to apply ratios and energy calculations to find the solution, with some participants suggesting alternative scenarios for clarity.

Discussion Status

Some participants have provided guidance on relevant formulas and concepts, while others are exploring different interpretations of the problem. The discussion is ongoing, with no explicit consensus reached yet.

Contextual Notes

There is a mention of potential confusion regarding the application of the heat transfer equation and the need for clarity on the setup of the problem. The original poster expresses difficulty in finding the resulting temperature, indicating a possible gap in understanding the principles involved.

ijaz
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Homework Statement



How much water at 82 degrees celsius must be added to 1.00kg of water at 14 degrees celsius to give it a final temperature of 36 degrees celsius

Homework Equations



qgained=-qlost??

The Attempt at a Solution


finding the resulting temperature, never works out for me please help
 
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If added 1 kg of water at 16 degress to the 1 kg of water at 14 degrees, what would you expect the temperature of the resulting 2 kg of water to be?
 
Last edited by a moderator:
Suppose it takes X joules of energy to raise 1Kg of water 1 degree.
You need to increase 1Kg of water by 36-14 = 22 degrees.
You are going to do this by adding water that is 82-14 = 68 degrees hotter.
Then it's just a matter of ratios.

Suppose you added 1Kg it would end up at half way between 14 and 86 = 14 + (86-14)/2 = 50deg so you need less than 1kg
 
Where is your work?

Perhaps to get started, are you aware of this formula?
[tex] m_1 c_1 \left( {T_1 - T_F } \right) = m_2 c_2 \left( {T_F - T_2 } \right)[/tex]
 

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