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Please see the attached file.When does the graph of

  1. Jul 21, 2012 #1
    Please see the attached file.

    When does the graph of x(t)=5/6*sin⁡(10t-0.927) equal 5/12

    5/12=5/6*sin⁡(10t-0.927)

    One answer, attached, is when the graph goes through the green points but I can't seem to figure out how to calculate the values of the red points.

    Any help would be greatly appreciated.
     

    Attached Files:

  2. jcsd
  3. Jul 21, 2012 #2

    haruspex

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    Re: x(t)=5/6*sin⁡(10t-0.927)

    The value of the function arcsin(y) is defined to be the solution of sin(x) = y that lies in the range (-π/2, +π/2]. There is a second solution π-arcsin(y) in the range (+π/2, +π]. This will form the basis of the 'red' points.
     
  4. Jul 21, 2012 #3
    Re: x(t)=5/6*sin⁡(10t-0.927)

    Oh, yep, duh.

    Thank you very much for your help.
     
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