Please somebody help me with this problem

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SUMMARY

The discussion centers on calculating the minimum static coefficient of friction (μs) required for a 220kg refrigerator to resist movement when a 100kg mover applies a horizontal force of 500N. The forces acting on the refrigerator include its weight, the normal force, and the applied force. The maximum static friction force can be determined using the equation F_friction = μs * N, where N is the normal force equal to the weight of the refrigerator (approximately 2156N). The minimum static coefficient of friction necessary for the refrigerator to remain stationary is calculated as μs = F_applied / N.

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angina1
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I am looking for help to solve this problem A 100kg mover is trying to push a 220kg refrigerator with a force F=500N at 0 degrees. Draw or describe free-body diagram showing all the forces acting on the refrigerator and calculate the minimum static coefficient of friction us between the refrigerator and the floor that is necessary for the refrigerator to resist any movement.

I know that the forces acting in the vertical direction is a normal force and the weight of the refrigerator but I am confused about the forces acting in the horizontal direction
 
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The mover is exerting the horizontal force on the refrigerator. They don't tell you what kind of shoes the mover has (what their coefficient of friction is), so assume that the mover is somehow braced against something. Besides, at only 100kg compared to the 220kg refigerator, the mover had better have something to brace against, or else they need to put something slippery (or dowels) under the 'fridge.

What is the equation for the maximum horizontal static friction force that the 220kg object can generate, given its mass and coefficient of static friction?
 

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