Please very my solution: complex analysis

[squaremeplz]

Homework Statement

1) consider

$$az - b*conj(z) + c = 0$$

where a,b,c are complex unknown constans

express z in terms of a,b,c

Homework Equations

The Attempt at a Solution

ok so i took the conjugate of the original equation to get a second equation:

$$a*conj(z) - b*z + c = 0$$

so my two equations are

1) $$az - b*conj(z) + c = 0$$

2) $$a*conj(z) - b*z + c = 0$$

in order to get rid of the conj(z) i multiply the top by a and bottom by b

1) $$a^2z - ab*conj(z) + ac = 0$$

2) $$ab*conj(z) - b^2z + bc = 0$$

i simply add and simplify and my answer is

$$z = -\frac {a+b}{a^2-b^2} * c$$

does this seem correct?

 

[n!kofeyn]

If the problem states that a,b,c are complex constants, then when you conjugate the entire equation, you need to conjugate these constants as well.

 

[squaremeplz]

ok, woul the final answer just be my answer with conjugate signs above all the constants?