Ploting a graph of kinetic energy of mass

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SUMMARY

The discussion focuses on plotting the kinetic energy of a 6 kg mass subjected to a horizontal force of 80 N. The mass accelerates at 11.81474 m/s², covering 5 m in 0.92 seconds. The kinetic energy (KE) is calculated using the formula KE = 1/2 mv², resulting in a maximum value of 418.117 J. Participants discuss how to plot KE against time and distance, emphasizing the need to account for changing velocity as the mass accelerates.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Familiarity with the kinetic energy formula (KE = 1/2 mv²)
  • Basic knowledge of graph plotting techniques
  • Ability to calculate acceleration and velocity from force and mass
NEXT STEPS
  • Learn how to derive velocity as a function of time for accelerating objects
  • Explore graphing software tools like Desmos or GeoGebra for plotting physics graphs
  • Study the relationship between kinetic energy and distance traveled
  • Investigate the effects of varying forces on acceleration and kinetic energy
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the dynamics of motion and energy calculations.

JavaJoeUK2011
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A horizontal force of 80N acts on a mass of 6Kg resting on a horizontal surface. The mass is initially at rest and covers a distance of 5m in 0.92s under the action of the force. Assuming there are no energy losses due to air resistance and therefore that the acceleration is constant.

1.Plot a graph of the kinetic energy of the mass against time.


d = (1/2)at2 = (1/2)(11.81474m/s2)(0.92s)2 = 5m

v= 11.814 m/s2

KE = 1/2 mv^2 = 1/2 x 6 x 11.814^2 = 418.117

So x-axis would be KE of Mass 0 to 418.177 and y-axis would be time 0 to .092


2.Plot a graph of the kinetic energy of the mass against distance.

So x-axis would be KE of Mass 0 to 418.177 and y-axis would be Distance 0 to .5

Have i done this correctly?
 
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Hi JavaJoeUK2011! :smile:

You need to find the KE as a function of t. :wink:
 
looks like I am doing a similar assignment.
I have plotted the graph of KE against time and the the KE figure has changed with the value V being altered at each point depending on T.
So at 0.92, KE =1/2mv^2
with v=at = 11.8 x 0.92=10.8
so KE=0.5 x 6 x 10.8 =349.92

Is this correct?
If so how do I figure in the changes in distance?
 
I would just like to know what calculation you use for you to get 11.8 m/s squared?
Im struggling to calculate a single Velocity knowing that the mass is accelerating?
 

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