MHB Plotting a Polar Equation of a Circle on Desmos

  • Thread starter Thread starter karush
  • Start date Start date
  • Tags Tags
    Desmos Polar
AI Thread Summary
To plot a circle in polar coordinates with a radius of 2 and center at (4,0), the initial equation derived is r^2 - 8r cos(θ) = -12. However, this does not yield a visible plot in Desmos. The Cartesian form of the circle is (x-4)^2 + y^2 = 2^2, which simplifies to x^2 + y^2 = 8x - 12 when converted to polar coordinates. For successful plotting in Desmos, the equation must be rearranged to isolate r. Properly isolating r is essential for accurate representation in polar form.
karush
Gold Member
MHB
Messages
3,240
Reaction score
5
The given is
determine a polar equation for circle satisfying the given conditions: the radius is $2$, and the polar coordinates for the center are: $\left(4,0\right)$
I got ${r}^{2}-8r\cos\left({\theta}\right)=-12$
But when I try to plot this to DESMOS get nutin.
 
Last edited:
Physics news on Phys.org
I would begin with the Cartesian equation of that circle:

$$(x-4)^2+y^2=2^2$$

$$x^2-8x+16+y^2=4$$

$$x^2+y^2=8x-12$$

Convert to polar:

$$r^2=8r\cos(\theta)-12$$

Try W|A for polar plots:

W|A - r^2=8rcos(theta)-12
 
Apparently r has to be isolated for Desmos
 

Similar threads

Replies
7
Views
3K
Replies
2
Views
929
Replies
5
Views
2K
Replies
5
Views
2K
Replies
1
Views
2K
Replies
7
Views
2K
Back
Top