Plotting Complex Functions: Does it Look Like a Riemann Surface?

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SUMMARY

The discussion confirms that the plots of the real and imaginary parts of the complex function \(z^{1/3}\) resemble the Riemann surface defined by the equation \(w^3 = z\). The Riemann surface is represented in four-dimensional space as \(\{(w_0, w_1, z_0, z_1) \in \Bbb R^4 \, :\, (w_0 + iw_1)^3 = z_0 + iz_1\}\). When plotting the real part, the representation is \(\{(x, y, z) \in \Bbb R^3 \, : \, z = \Re[(x+iy)^{1/3}]\}\), indicating that these plots are sections of the original Riemann surface, albeit deformed around the branch points. Thus, the visual similarity to the Riemann surface is established as accurate.

PREREQUISITES
  • Understanding of complex functions, specifically \(z^{1/3}\)
  • Familiarity with Riemann surfaces and their mathematical definitions
  • Knowledge of real and imaginary parts of complex numbers
  • Basic skills in 3D plotting techniques
NEXT STEPS
  • Explore the mathematical properties of Riemann surfaces in depth
  • Learn advanced 3D plotting techniques using tools like Matplotlib or MATLAB
  • Investigate branch cuts and their effects on complex function plots
  • Study the implications of multi-valued functions in complex analysis
USEFUL FOR

Mathematicians, students of complex analysis, and anyone interested in visualizing complex functions and their properties.

Dustinsfl
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I plotted the real and imaginary parts of a complex function \(z^{1/3}\). The two plots are similar to the Riemann surface is that correct?

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Recall that the Riemann surface of $w^3 = z$ is defined to be

$$\{(w_0, w_1, z_0, z_1) \in \Bbb R^4 \, :\, (w_0 + iw_1)^3 = z_0 + iz_1\}$$

While taking the real part you are really plotting

$$\{(x, y, z) \in \Bbb R^3 \, : \, z = \Re[(x+iy)^{1/3}]\}$$

So that's bound to be a section of the original Riemann surface, a bit deformed around the branches. Similar holds for the imaginary part.

So yes, those indeed look similar to the original Riemann surface.
 

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