Plotting Stopping Voltage vs. Frequency

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The discussion revolves around the relationship between stopping voltage and frequency in a physics context, specifically regarding the interpretation of slope and intercept in the equation Vs = (h/e)f - (work function/e). Participants debate the correct interpretation of the slope and intercept, with option (a) suggesting the slope relates to Planck's constant and the intercept to the work function being favored. Clarifications are requested on the terminology used, as some find the phrasing confusing. Overall, the conversation emphasizes the need for precise language in scientific discussions. Understanding these relationships is crucial for accurate analysis in physics.
bravellama
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Homework Statement



Plotting stopping voltage vs. frequency, we expect to find:
a) the slope is related to Planck's constant and the intercept is related to the work function of the metal

b) the slope is related to the work function of the metal and the intercept is related to Planck's constant

c) the slope is the work function of the metal divided by Planck's constant and the intercept is irrelevant

d) the intercept is Planck's constant divided by the work function of the metal and the slope is irrelevant

Homework Equations



Vs= (h/e)f - (work function/e)


The Attempt at a Solution


I think the answer is (A) because the Planck's constant is the slope and the intercept is the work function, but I am not sure. Any help would be great :)
 
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"planck's constant is the slope" is a bit strange. Idem "the intercept is the work function".
Fortunately the wording of a) is more accurate :smile:

For the uninitiated: this is not about Foucault's pendulum! But about ... ?
(meaning: try to be a bit more complete under 1)...
 
Thank you so much for clarifying. I thought the wording too was unclear.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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