Plotting the position of a pendulum

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SUMMARY

The discussion focuses on solving the position of a pendulum, specifically determining the horizontal coordinate of the pendulum bob's shadow when the sun is directly overhead. The governing differential equation is d²θ/dt² = -(g/l) sin(θ), where g represents gravitational acceleration, l is the pendulum length, and θ is the angle with the vertical. For small angles, the equation simplifies to d²θ/dt² = -(g/l)θ, leading to the general solution θ(t) = C cos(√(g/l) t) + D sin(√(g/l) t), where C and D are determined by initial conditions.

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  • Knowledge of gravitational potential energy (PE) and kinetic energy (KE) equations
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bassplayer142
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Does anyone know where I could find some information about solving a pendulum position. What I mean is a swinging pendulum and the position. The position would be the spot on the ground that a sun directly above would cast. I don't really know where to start other then the pythagorean theorum, Ke and Pe equations. Any help would be great. thanks
 
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The simple pendulum satisfies the differential equation [itex]d^2\theta/dt^2[/itex]= -(g/l) sin(\theta)[/itex] where g is the acceleration due to gravity, l is the length of the pendulum, t is the time, and [itex]\theta[/itex] is the angle the pendulum makes with the vertical. Assuming the sun is directly overhead the shadow of the pendulm bob will be the horizontal coordinate, [itex]l cos(\theta)[/itex].

That is an extremely difficult equation to solve but for small angles, [itex]sin(\theta)[/itex] is approximately equal to [itex]\theta[/itex] so the equation can be approximated by [itex]d^2\theta/dt^2= -(g/l)\theta[/itex] which has general solution
[tex]\theta(t)= C cos(\sqrt{g/l} t)+ D sin(\sqrt{g/l} t)[/tex].

Determine C and D by the intitial value of [itex]\theta[/itex] and the angular velocity.
 
thanks a lot!
 

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