Point charges arranged as a trianngle

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SUMMARY

The discussion focuses on calculating the electric force components acting on charge qC located at the vertex of an equilateral triangle formed by charges qA and qB. The charges are specified as qA = +2 µC, qB = +2 µC, and qC = -1 µC, with a side length of a = 7 cm. The user initially miscalculates the force due to incorrect application of the formula F = kqAqC/r², leading to confusion in determining the y-component of the force. The correct approach involves ensuring the distance is converted properly from centimeters to meters and applying the formula accurately to find the resultant force.

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jenzao
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Homework Statement


Consider three charges at the vertices of an equilateral triangle of side a = 7 cm. qA = +2 µC, qB = +2 µC, and qC = -1 µC. (see attached picture)

Find the x- and y- components of the electric force acting on qC



Homework Equations


i am doing everything right, but getting wrong answer ?


The Attempt at a Solution


x-comp cancel obviously, so I am left with finding y-comp...

F = kqAqC/r^2
= 2.571e-1

sin60(2.571e-1) = 2.2266e-1
multiply by 2 = 4.453e-1 N (this is wrong though)

i can't see the prob. The forces both point in positive y direction, so the y vectors sum
please help, thanks!
 

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jenzao said:

The Attempt at a Solution


x-comp cancel obviously, so I am left with finding y-comp...

F = kqAqC/r^2
= 2.571e-1

sin60(2.571e-1) = 2.2266e-1
multiply by 2 = 4.453e-1 N (this is wrong though)
=k.qA.qC/r^2
=9E9 x 2E-6 x 1E-6/0.07^2
=3.67

I see you are dividing by 7
Two mistakes it's 7cm and then its r^2
 

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