Pointwise Convergence in Metric Space (C[a,b],d_{\infty}) | Homework Solution

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SUMMARY

The discussion focuses on the proof of pointwise convergence of a sequence of functions \( (f_n)_{n\in\mathbb{N}} \) to a limit function \( f \) in the metric space \( (C[a,b], d_{\infty}) \). It establishes that if \( f_n \to f \) in the uniform metric, then \( f_n(t) \to f(t) \) for each \( t \in [a,b] \). However, participants caution against conflating pointwise convergence with uniform convergence, emphasizing that the implications must be carefully directed to avoid logical errors.

PREREQUISITES
  • Understanding of metric spaces, specifically \( (C[a,b], d_{\infty}) \)
  • Knowledge of uniform convergence and pointwise convergence of functions
  • Familiarity with the uniform metric defined as \( d_{\infty}(f,g) = \text{max}_{t\in [a,b]} |f(t)-g(t)| \)
  • Basic proof techniques in real analysis
NEXT STEPS
  • Study the differences between pointwise and uniform convergence in detail
  • Explore counterexamples that illustrate the distinction between pointwise and uniform convergence
  • Learn how to construct rigorous proofs in real analysis, focusing on implications and logical flow
  • Investigate the implications of convergence in various function spaces beyond \( C[a,b] \)
USEFUL FOR

Students of real analysis, mathematicians focusing on functional analysis, and anyone interested in the properties of convergence in metric spaces.

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Homework Statement



Suppose a sequence (f_n)_{n\in\mathbb{N}} converges to a limit f in the metric space (C[a,b],d_{\infty}) (continuous real valued functions on the interval [a,b] with the uniform metric.)

Show that f_n also converges pointwise to f; that is for each t\in [a,b] we have f_n(t)\to f(t) in \mathbb{R}.

Homework Equations



Uniform metric: d_{\infty} (f,g) = \text{max}_{t\in [a,b]} |f(t)-g(t)|

The Attempt at a Solution



f_n \to f in (C[a,b],d_{\infty}) \iff d_{\infty}(f_n,f)\to 0

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\, \iff \text{max}_{t\in [a,b]} |f_n(t)-f(t)| \to 0

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\, \iff|f_n(t)-f(t)| \to 0 for all t\in [a,b]

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\, \iff f_n(t) \to f(t) for all t\in [a,b]

Does this prove it?
 
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Looks ok to me.
 
Ted123 said:

Homework Statement



Suppose a sequence (f_n)_{n\in\mathbb{N}} converges to a limit f in the metric space (C[a,b],d_{\infty}) (continuous real valued functions on the interval [a,b] with the uniform metric.)

Show that f_n also converges pointwise to f; that is for each t\in [a,b] we have f_n(t)\to f(t) in \mathbb{R}.

Homework Equations



Uniform metric: d_{\infty} (f,g) = \text{max}_{t\in [a,b]} |f(t)-g(t)|

The Attempt at a Solution



f_n \to f in (C[a,b],d_{\infty}) \iff d_{\infty}(f_n,f)\to 0

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\, \iff \text{max}_{t\in [a,b]} |f_n(t)-f(t)| \to 0

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\, \iff|f_n(t)-f(t)| \to 0 for all t\in [a,b]

\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\, \iff f_n(t) \to f(t) for all t\in [a,b]

Does this prove it?

You need to be careful what you are proving. You have all these \iff implications which would lead one to believe that pointwise convergence and uniform convergence are the same. But they aren't. So look at your argument carefully and make sure the implications go in the direction to prove what you want to prove.
 
LCKurtz said:
You need to be careful what you are proving. You have all these \iff implications which would lead one to believe that pointwise convergence and uniform convergence are the same. But they aren't. So look at your argument carefully and make sure the implications go in the direction to prove what you want to prove.

Good point!
 
Obviously to prove what I want I only need all steps to be \implies but which step above is not "if and only if"? (is it the last step?)
 
|f_n(t)-f(t)|->0 for all t does not imply max |f_n(t)-f(t)|->0. Can you think of a counterexample?
 
Ted123 said:
Obviously to prove what I want I only need all steps to be \implies but which step above is not "if and only if"? (is it the last step?)

Dick said:
|f_n(t)-f(t)|->0 for all t does not imply max |f_n(t)-f(t)|->0. Can you think of a counterexample?

And I would add that if I were handing in a proof, I would use a tighter argument. While your implications in one direction are OK, you wouldn't have made that mistake if your argument went something like:

0 \le |f_n(t)-f(t)| \le ... \rightarrow 0

where you fill in the dots with reasons for each step.
 

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