sarahp6888 Messages 2 Reaction score 0 Thread starter May 27, 2009 #1 For the sequence of functions fn(x)=ne^(-xn^2) on [0,infinity), what is the pointwise limit of this sequence?is the converbence uniform?
For the sequence of functions fn(x)=ne^(-xn^2) on [0,infinity), what is the pointwise limit of this sequence?is the converbence uniform?
Count Iblis Messages 1,859 Reaction score 8 May 28, 2009 #2 Limit functon f(x) is: f(x) = 0 for x > 0 f(0) is not defined because for x = 0 the sequence diverges. Because f(x) is not continuous while all the f_n(x) are continuous, the convergence is not uniform.
Limit functon f(x) is: f(x) = 0 for x > 0 f(0) is not defined because for x = 0 the sequence diverges. Because f(x) is not continuous while all the f_n(x) are continuous, the convergence is not uniform.