- #1
AHSAN MUJTABA
- 89
- 4
Summary:: I have been provided with the table in which N and occurence are given. I have been asked to calculate the 1. Total count 2. mean count 3. mean count.
Now, assuming our distribution described by Poisson's we need to calculate the tasks.
The Poisson's distribution is given by: ##P(N,\bar N)=\frac{exp(-\bar N)\bar N^{N}}{N!}##
The expected value are calculated as, ##\bar N=\Sigma P N##
As long as I understood the attached question, I have following attempt to the questions.
1. I took the sum over all N that came out to be = 89 (the total number of counts recorded)
2. I took a simple data mean with ##\frac{n}{N}## for which n=total number of data points I have right now i.e. n=12
3. I calculated the mean number of counts $\bar N$ by the fact that there are 58 trials so ##\bar N=\frac{N}{no. of occurences}=\frac{89}{58}=1.5345 \frac{counts}{sec}##
4. In this part I am confussed because it asks me to calculate the expected no of occurences but by the given formulae I am unable to understand whether I should calculate ##\bar N##.
Now, assuming our distribution described by Poisson's we need to calculate the tasks.
The Poisson's distribution is given by: ##P(N,\bar N)=\frac{exp(-\bar N)\bar N^{N}}{N!}##
The expected value are calculated as, ##\bar N=\Sigma P N##
As long as I understood the attached question, I have following attempt to the questions.
1. I took the sum over all N that came out to be = 89 (the total number of counts recorded)
2. I took a simple data mean with ##\frac{n}{N}## for which n=total number of data points I have right now i.e. n=12
3. I calculated the mean number of counts $\bar N$ by the fact that there are 58 trials so ##\bar N=\frac{N}{no. of occurences}=\frac{89}{58}=1.5345 \frac{counts}{sec}##
4. In this part I am confussed because it asks me to calculate the expected no of occurences but by the given formulae I am unable to understand whether I should calculate ##\bar N##.