Polarity of a horseshoe shaped solenoid

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Homework Help Overview

The discussion revolves around determining the polarity of a horseshoe-shaped solenoid based on the direction of current flow and the wrapping of the wire. The original poster expresses confusion regarding the application of the right-hand grip rule and the conflicting results obtained from viewing the solenoid from different ends.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the right-hand grip rule to determine the north and south poles of the solenoid based on the current direction and wire wrapping. Some participants question whether the rules should be applied differently, considering the solenoid's shape.

Discussion Status

Participants are exploring the implications of the right-hand grip rule and discussing the expected outcomes of the solenoid's polarity. Some guidance has been offered regarding the application of the rule, but there is still some uncertainty about the correct interpretation of the results.

Contextual Notes

The original poster mentions a symbol for the power source and describes the current flow, but there are no specific equations provided. The discussion reflects a lack of consensus on how to interpret the current direction and wire wrapping in relation to the solenoid's polarity.

Abigaile
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Homework Statement



polarity of a horseshoe shaped solenoid given symbol for power source large line small line.
Current flows through the right end of the horsehoe and out of the left end.

The wire is wrapped in a CW direction if looking at the left end of the magnet.
The wire is wrapped in a ACW direction if looking at the right end of the magnet.

Im confused that the current direction using right hand grip rule and wrap direction of the coil viewed from the ends are giving the opposite conflicting result.

Homework Equations



none

The Attempt at a Solution



Assuming conventional current from positive (large line) to negative (small line).

Viewing the right end current direction is ACW so this should be North
Viewing the left end current direction is CW so this should be South

Is this correct or should I consider the rules as if the horseshoe was broken in half like a wishbone?

Thanks..
 
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Hi Abigaile! Welcome to PF! :smile:
Abigaile said:
polarity of a horseshoe shaped solenoid …
Current flows through the right end of the horsehoe and out of the left end.

The wire is wrapped in a CW direction if looking at the left end of the magnet.
The wire is wrapped in a ACW direction if looking at the right end of the magnet.

Im confused that the current direction using right hand grip rule and wrap direction of the coil viewed from the ends are giving the opposite conflicting result.

No. :confused:

Wrap your right hand around the left end of the solenoid, so that your fingers are curling the same way as the current …

your thumb then points into the solenoid.

Now slide your hand all the way round the solenoid to the other end …

your thumb now points out of the solenoid …

isn't that what you expect, one end north and the other end south? :smile:
 


tiny-tim said:
Hi Abigaile! Welcome to PF! :smile:


No. :confused:

Wrap your right hand around the left end of the solenoid, so that your fingers are curling the same way as the current …

your thumb then points into the solenoid.

Now slide your hand all the way round the solenoid to the other end …

your thumb now points out of the solenoid …

isn't that what you expect, one end north and the other end south? :smile:

Hi Tim :smile:

does that mean left end is south and right end is north?:wink:
 
Yes! :smile:

(or the other way round … i can't remember o:))
 

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