a certain bifringement material has indexes of refraction n(adsbygoogle = window.adsbygoogle || []).push({}); _{1}and n_{2}for the two perpendicular components of linearly polarized light passing through it. the corresponding wavelengths are λ_{1}=λ_{0}/n_{1}and λ_{2}=λ_{0}/n_{2}, where λ_{0}is wavelength in vacuum. If crystal is to function as a quarter-wave plate, the number of wavelengths of each component within a material must differ by 1/4. show that the minimum thickness for a quarter-wave plate is

d=λ_{0}/[4(n_{1}-n_{2})]

i have no idea. i can see all the numbers are there, but i cant see how to actually "show" it.

thanks

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# Homework Help: Polarization: minimum thickness for quater-wave plate

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