Polarization: minimum thickness for quater-wave plate

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SUMMARY

The minimum thickness for a quarter-wave plate made from a birefringent material is determined by the formula d=λ0/[4(n1-n2)], where λ0 is the wavelength in vacuum and n1 and n2 are the indices of refraction for the two perpendicular components of linearly polarized light. This relationship ensures that the optical path difference between the two components is exactly one-quarter of the wavelength. The discussion highlights that typical zero-order wave plates are very thin, generally less than 100 micrometers, and crystal quartz is commonly used as the material for these applications.

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ProPatto16
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a certain bifringement material has indexes of refraction n1 and n2 for the two perpendicular components of linearly polarized light passing through it. the corresponding wavelengths are λ10/n1 and λ20/n2, where λ0 is wavelength in vacuum. If crystal is to function as a quarter-wave plate, the number of wavelengths of each component within a material must differ by 1/4. show that the minimum thickness for a quarter-wave plate is

d=λ0/[4(n1-n2)]

i have no idea. i can see all the numbers are there, but i can't see how to actually "show" it.

thanks
 
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ProPatto16 said:
a certain bifringement material has indexes of refraction n1 and n2 for the two perpendicular components of linearly polarized light passing through it. the corresponding wavelengths are λ10/n1 and λ20/n2, where λ0 is wavelength in vacuum. If crystal is to function as a quarter-wave plate, the number of wavelengths of each component within a material must differ by 1/4. show that the minimum thickness for a quarter-wave plate is

d=λ0/[4(n1-n2)]

i have no idea. i can see all the numbers are there, but i can't see how to actually "show" it.

thanks

Yes, usually true zero-order wave plate is very thin, <100um depends on wavelength.
The mostly used material is crystal quartz.
What optical wavelength you are using?
Maybe I can help to design, email: charles.chen@photonik.com.sg
 

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