Polarized wave in an anisotropic medium

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The discussion focuses on calculating the wavelength of an E_x polarized wave in an anisotropic medium characterized by the permittivity tensor ε and permeability tensor μ. The user initially struggles to determine the wave vector k_y and the wavelength in terms of free space wavelength λ_0. It is clarified that the wavelength in an anisotropic medium can be derived using the relevant components of the permittivity and permeability tensors. The conclusion reached is that for the given anisotropic material, the wavelength remains equal to λ_0 in both the y and z directions due to the specific polarization and tensor properties. Understanding the behavior of waves in anisotropic media is crucial for applications in optics and materials science.
lholmes135
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Homework Statement
Calculate the wavelength for an Ex polarized wave
Relevant Equations
Unsure
Calculate the wavelength for an ##E_x## polarized wave traveling through an anisotropic material with ##\overline{\overline{\epsilon}}=\epsilon_0diag({0.5, 2, 1})\text{ and }\overline{\overline{\mu}}=2\mu_0## in:
a. the y direction
b. the z direction
Leave answers in terms of the free space wavelength.

All I've gotten so far is:
$$E(y, t)=E_0cos(k_yy-wt)$$
$$\lambda=\frac{2\pi}{k_y}$$
I don't know how to determine ##k_y## or ##\overline{k}##. I'm basically totally stumped on this problem. Of course it needs to be in terms of:
$$\lambda_0=\frac{2\pi c}{\omega_0}$$
 
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Do you know how to calculate the wavelength in an isotropic medium with (for example) ##\epsilon = 2 \epsilon_0## and ##\mu=2\mu_0##?

jason
 
Sure. ##\lambda=\frac{\lambda_0}{\sqrt{\epsilon_r\mu_r}}##, so in your example the wavelength would be half of that as in free space. The problem in anisotropic materials is that when ##\epsilon## and ##\mu## are tensors, I don't know what values to use.
 
I think I figured it out. Because the electric field is polarized in the x direction and the magnetic field in the z direction, I can just use the x component of permittivity and the z component of the magnetic field, so in this problem ##\lambda=\lambda_0## in both cases.
 

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