Polarized wave in an anisotropic medium

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SUMMARY

The discussion focuses on calculating the wavelength of an E_x polarized wave traveling through an anisotropic medium characterized by the permittivity tensor ##\overline{\overline{\epsilon}}=\epsilon_0diag({0.5, 2, 1})## and the permeability tensor ##\overline{\overline{\mu}}=2\mu_0##. The key conclusion is that the wavelength remains equal to the free space wavelength, ##\lambda=\lambda_0##, when considering the x component of permittivity and the z component of permeability. This result applies for both the y and z directions of wave propagation.

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  • Understanding of electromagnetic wave propagation in anisotropic media
  • Familiarity with tensor notation for permittivity and permeability
  • Knowledge of the relationship between wavelength, frequency, and wave number
  • Basic concepts of polarization of electromagnetic waves
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lholmes135
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Homework Statement
Calculate the wavelength for an Ex polarized wave
Relevant Equations
Unsure
Calculate the wavelength for an ##E_x## polarized wave traveling through an anisotropic material with ##\overline{\overline{\epsilon}}=\epsilon_0diag({0.5, 2, 1})\text{ and }\overline{\overline{\mu}}=2\mu_0## in:
a. the y direction
b. the z direction
Leave answers in terms of the free space wavelength.

All I've gotten so far is:
$$E(y, t)=E_0cos(k_yy-wt)$$
$$\lambda=\frac{2\pi}{k_y}$$
I don't know how to determine ##k_y## or ##\overline{k}##. I'm basically totally stumped on this problem. Of course it needs to be in terms of:
$$\lambda_0=\frac{2\pi c}{\omega_0}$$
 
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Do you know how to calculate the wavelength in an isotropic medium with (for example) ##\epsilon = 2 \epsilon_0## and ##\mu=2\mu_0##?

jason
 
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Sure. ##\lambda=\frac{\lambda_0}{\sqrt{\epsilon_r\mu_r}}##, so in your example the wavelength would be half of that as in free space. The problem in anisotropic materials is that when ##\epsilon## and ##\mu## are tensors, I don't know what values to use.
 
I think I figured it out. Because the electric field is polarized in the x direction and the magnetic field in the z direction, I can just use the x component of permittivity and the z component of the magnetic field, so in this problem ##\lambda=\lambda_0## in both cases.
 

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