Polyatomic ions and their charge

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SUMMARY

The discussion centers on understanding the charge of polyatomic ions, specifically selenate (SeO4) and its charge of -2. Participants clarify that the charge can be deduced by analyzing the oxidation states of the constituent atoms, particularly selenium and oxygen. The charge arises from the unpaired electrons in the oxygen atoms, leading to a stable electron configuration. The conversation emphasizes the importance of visualizing electron pairing to comprehend the overall charge of polyatomic ions.

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  • Understanding of oxidation states in chemistry
  • Familiarity with electron configuration and bonding
  • Knowledge of polyatomic ions and their structures
  • Basic principles of ionic charge determination
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  • Study the electron configuration of selenium and oxygen in detail
  • Learn about the formation and properties of common polyatomic ions
  • Explore the concept of oxidation states in more complex molecules
  • Investigate the Lewis structure representation of polyatomic ions
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icefire23
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This question is regarding polyatomic ions and their charge. I have always been told that I have to memorize the charge of polyatomic ions. The question is whether I can determine by myself the charge of two atoms when they join together to form a polyatomic ion. For example Se and O can form selenate SeO4, this polyatomic ion has a charge of -2. I would like to know why is the charge -2? But what I know the sum of all oxidation states of the joining ions must be equal to the net charge of the ion. But what happens then if I do not know the net charge of the ion? Hopefully these questions are not too silly. Thanks before hand, Aldo.
 
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Selenate.png


Because the ion is like this. There is 1 unpaired electrons on 2 oxygen atoms, giving it a charge of 2-.

For these kinds of ions, just try pairing up their electrons to get a stable electron configuration until you only have unpaired electrons left. You can then deduce the charge of the whole ion from that.
 
Ok, seeing the bonds in the ion helped. Thank you very much for your help. So, when I have the SeO3 anion with a charge of -2, I would have 1 Selenium Oxygen double bond and two Selenium Oxygen single bonds, with an electron pair in the Selenium? Aldo.
 
yeap.

btw, what's aldo?
 
Thanks again for your help. Hahahaha..Aldo is just my name : )
 
Bloodthunder said:
Selenate.png


Because the ion is like this. There is 1 unpaired electrons on 2 oxygen atoms, giving it a charge of 2-.

For these kinds of ions, just try pairing up their electrons to get a stable electron configuration until you only have unpaired electrons left. You can then deduce the charge of the whole ion from that.

I still don't get how SeO4 acquires a charge of 2-. I don't understand the diagram above either. Please explain in more plain language.
 

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